We will use the algebraic or ŇladderÓ method.
The independent string modes have a Hamiltonian and a Lagrangian:
The momentum conjugate to xn is:
Substituting into the Hamiltonian we have
Before we think of x and P as operators, we factor (knowing that there will be a commutation error):
Scaled appropriately, the terms on the right will be the lowering and raising operators. Expanding the product out while treating P and x properly as operators.
Remembering that and that we have set
The other way around yields:
Yielding a commutator:
We want
instead of n, so we have to scale our operators:
The frequency of the string oscillations is just n and all you have to do is apply a- and a+ to decrement and increment the number of quanta in mode n. Each mode n will need its own raising and lowering operators which we will indicate with a subscript.
Also – we have x and y directions that the oscillations can take place in (eventually more directions), so we will need operators for each directions. For now we will use a for the x direction and b for the y direction.
String theory doesnŐt work well in 2 dimensions. String theory is in 26 dimensions because we run out of letters past there :-)
Another useful thing to do with a- and a+ is to solve for x and p:
This allows us to express the string behavior in terms of these operators:
When we say a particle has spin J we mean that it has a maximum spin J. For spin J there are 2J+1 possible states ranging from –J to J in integer steps.
A massive particle has to have intermediate value of Sz. You can simply move into its rest frame and rotate the coordinate system. If you measured the particle as having spin J and then rotated the z-axis onto the x-axis, then Sz would measure a 0. So massive particles have intermediate spin values.
You canŐt move into the rest frame of a massless particle that always moves with velocity c. If you have a massless particle with spin J, then by reflection symmetry you also have spin –J. There is no reason to have spin values in between and we donŐt see them.
All photons are polarized. If you measure their spin, you get spin +1 or -1, never 0. A linearly polarized photon is a linear combination of left and right handed spin states. You can use the linear states or the circular states as basis states.
Like photons, gravitrons have only 2 states. They are often treated mathematically like two photons stuck together with the cross states outlawed. All that characterizes photons and gravitrons is momentum, energy, spin, polarization.
In the infinite momentum frame the energies correspond to m2.
There is a lowest energy state where:
(also true
for b)
Suppose that the ground state has energy .
(In a normal quantum harmonic oscillator it would be
).
The first excitation would be:
with
energy
(units still a mystery)
Note: the aŐs and bŐs behave like polarization components. They can be summed and rotated like vectors.
Circularly polarized raising operator:
raises the ground state energy one unit
[Maybe we should really be writing
this as
]
These first excitation objects are behaving as photon like objects.
[Actually, I am a bit confused
here. I get that the state
of the first excitation has a polarization just like a photon. However, unlike a photon there is no Z direction to move in. Perhaps the only way to
make this all consistent is in the limit where the string is moving at along z.]
If they are photon like objects, then their internal energy must be 0 and:
But this leads to the intolerable requirement that
This leads to tachyons, which are bad.
Some history of tachyons
With relativity, velocity is a simple function of momentum and total energy:
if , then
.
What is wrong with this? The answer is that the vacuum is unstable.
Take the wave equation
To add a mass term [see last couple of quarterŐs notes] we can just add a potential term based directly on the field.
Which has a potential energy term that climbs with the field
strength. In the case of a tachyon
with we get:
And now the potential energy term is an upside down parabola. Any disturbance will lead to the field increasing without bound. The effect of this disturbance will then propagate at the speed of light, so tachyons donŐt actually result in propagation of information faster than light.
There is also no ground state – generally a bad thing.
We need to rescue the string theory from this fate. The answer is ŇSuperÓ string theory. [I assume the super has something to do with super-symmetry] We will come to this, but for now lets assume that we can eliminate the tachyons from the theory.
Originally, when string theory was being applied to hadron physics, there was an unsuccessful effort to also eliminate the photons. Later, the photon like behavior became an asset instead of a problem.
The basic interaction mode of strings is for endpoints to join (or break apart). There is a generally a single coupling constant for this to occur should the endpoints be at the same location. This coupling constant is independent of the state of the string, but obviously a faster moving string would be near another string for less time, so the state of strings does affect interaction.
Anything that can happen can be reversed (strings can break)
Strings may just pass through each other.
A string can join itself, creating a closed loop
Any string can absorb or emit a closed loop.
The fact that all strings interact with closed loops in a consistent way is important since we expect all strings to gravitate.